A solution of HCl contains 0.1920 g of an acid in 0.5 litre of a solution. The degree of dissociation is 95%. The pH of the solution is

Concentration C of HCl solution=0.192036.5 × 0.5 = 0.010 MThe degree of dissociation is 95%, i.e.,95100 = 0.95Therefore, H+=0.010 × 0.95 = 0.0095pH=-log H+ = -log 0.0095  = --2.02 = 2.02≈2.0