A solution is a mixture of 0.05 M NaCI and 0.08 M NaI. The concentration of iodide ion in the solution when AgCl just starts precipitating is equal toKsp(AgCl)=1×10−10M2;Ksp(AgI)=4×10−16M2
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a
4×10−6M
b
2×10−8M
c
2×10−7M
d
8×10−15M
answer is C.
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Detailed Solution
Ksp (AgCl) Ksp (AgI) hence, AgI is precipitated before AgCl. [ Ag+] to precipitated Cl−=1×10−100.05=2×10−9MI−at this stage =Ksp(AgI)Ag+=4×10−162×10−9=2×10−7M