First slide

Nernst Equation

Question

The solution of nickel sulphate in which nickel rod is dipped is diluted 10 times. The potential of nickel

Easy

Solution

Half cell reaction is Ni⁺² +2e^- → Ni
Applying Nernst equation
${E_{N{i^{ + 2}}/Ni}} = E_{N{i^{ + 2}}/Ni}^o - \frac{{0.0591}}{2}\log \frac{{\left[ {Ni} \right]}}{{\left[ {N{i^{ + 2}}} \right]}}$
${E_{N{i^{ + 2}}/Ni}} = E_{N{i^{ + 2}}/Ni}^o + \frac{{0.0591}}{2}\log \left[ {N{i^{ + 2}}} \right]$
Since the solutioin is 10 times diluted; [Ni]⁺² decreases 10 times. [Ni]⁺² =0.1M
${E_{N{i^{ + 2}}/Ni}} = E_{N{i^{ + 2}}/Ni}^o + \frac{{0.0591}}{2}\log {10^{ - 1}} = E_{N{i^{ + 2}}/Ni}^o - 0.0295$
Reduction potential decreases by approximately 30mV

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