A solution is obtained by dissolving 12 g of urea (mol. wt. 60) in a litre of water. Another solution is obtained by dissolving 68.4 g of cane sugar (mol. wt. 342) in a litre of water at the same temperature. The lowering of vapour pressure in the first solution is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Same as that of 2nd solution
b
Nearly one-fifth of the 2nd solution
c
Double that of 2nd solution
d
Nearly five times that of 2nd solution
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
We know that in the first solution number of the moles of urea= Mass of uream.wt. of urea×1V=1260×11=0.2 and, In second solution the number of moles of cane sugar =Mass of cane sugarm.wt. of cane sugar=68.4342×11=0.2