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The solution of a sparingly soluble salt Ax By in water is 'S" moles per. the solubility product has the value;

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a

S2

b

xyyx·Sx+y

c

xxyySx+y

d

Sx+y

answer is C.

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Detailed Solution

AxBy(s)⇌x·A(aq. )y++y·B(aq. )x- t = a α teq. (a-s) (x·s) (x·y) ksp=Ay+xBx-y =(x·s)x(y·s)y

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