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Q.

A solution of two components containing n1 moles of the 1st component and n2 moles of the 2nd component is prepared. M1 and M2 are the molecular weights of component 1 and 2 respectively. If d is the density of the solution in g mL-1, C2 is the molarity and x2  is the mole fraction of the 2nd component, then C2 can be expressed as

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a

C2=dx1M2+x2M2−M1

b

C2=dx2M2+x2M2−M1

c

C2=1000dx2M1+x2M2−M1

d

C2=1000x2M1+x2M2−M1

answer is C.

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Detailed Solution

C2=n2V(ml)×1000 →1d=mV(ml)⇒V=mdm=n1M1+n2M2V=n1M1+n2M2d →2x2=n2n1+n2 ⇒ n2=x2n1+n2 →3 Substitute V,n2 values in equation 1⇒ C2=x2n1+n21000dn1M1+n2M2=x21000dx1M1+x2M2=x21000d1−x2M1+x2M2=1000dx2M1+M2−M1x2
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