Q.
A solution of urea in water has boiling point of 100.15oC. Calculate the freezing point of the same solution if Kf and Kb for water are 1.87 K kg mol-1 and 0.52 K kg mol-1 respectively.
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a
−0.54oC
b
−0.44oC
c
−0.64oC
d
−0.34oC
answer is A.
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Detailed Solution
ΔTb=(100.15−100)=0.15oCWe know that, ΔTb=molality × KbMolality=ΔTbKb=0.150.52=0.2884ΔTf=molality×Kf=0.2884×1.87=0.54oCThus, the freezing point of the solution=−0.54oC.
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