A solution of x moles of sucrose in 100 grams of water freezes at −0.2oC. As ice separates the freezing point goes down to 0.25oC. How many grams of ice would have separated?

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18 gram

20 gram

25 gram

23 gram

answer is B.

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Detailed Solution

ΔTf=m×Kf∆Tf1∆Tf2= m1m2 -0.2-0.25=x×1000100x×1000WIn grams 0.20.25=W100W=80 grHence,the grams of ice that would be seperated =100-80=20 gr

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