A 5% solution(by mass) of cane sugar in water has freezing point of 271k and freezing point of pure water is 273.15k. The freezing point of a 5% solution (by mass) of glucose in water is

FP of pure water = 273.15KFP of 5% (W/W) C12H22O11(aq.) = 271KFP of 5% (W/W) C6H12O6(aq.) = ? the solvent is water in both casesBy comparing Sucrose and glucose solutions;                                                                                                                                                              both are 5% by mass                                                                                                                                                                                  Tf = FP of glucose sol. =273.15 - 4.085 =269.07K