In the Solvay process for producing sodium carbonate (Na2CO3), the following reactions occur in sequenceNH3+CO2+H2O⟶NH4HCO3NH4HCO3+NaCl⟶NH4Cl+NaHCO32NaHCO3⟶ΔNa2CO3+H2O+CO2How much of Na2CO3 would be produced per kg of NH3 used if the process were 100% efficient?

Given reaction is not balancedBased on stoichiometry1 mol Na2CO3 is from 2 mol NaHCO32 mol NaHCO, is from 2 mol NH4HCO32 mol NH4HCO3 is from 2 mol NHIThus, 1 mol Na2CO3 is from = 2 mol NH3106 g NarCO3 is from = 2 × 17 g NH334 g NH3 gives = 106 g Na2CO3  Thus, 1000gNH3 gives =106×100034gNa2CO3=3118gNa2CO3=3.118kgNa2CO3