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Q.

Some amount of solid NH4HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm.  Ammonium hydrogen sulphide decomposes to yield NH3 and H2S gases in the flask. When the decomposition reaction reaches equilibrium the total pressure in the flask rises to 0.84 atm. The equilibrium constant for NH4HS  decomposition at this temperature is

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answer is 4.

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Detailed Solution

Intial pressure of mixture containing NH4HS(s) and NH3(g) = 0.5 atmFor every one mole of NH3 formed, one mole of H2S is formed.Peq = 0.84Increase in pressure due to decomposition of NH4HS = (0.84 - 0.5) atm = 0.34 atmIncrease in pressure is due to formation of equal amounts of NH3 & H2S
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Some amount of solid NH4HS is placed in a flask already containing ammonia gas at a certain temperature and 0.50 atm.  Ammonium hydrogen sulphide decomposes to yield NH3 and H2S gases in the flask. When the decomposition reaction reaches equilibrium the total pressure in the flask rises to 0.84 atm. The equilibrium constant for NH4HS  decomposition at this temperature is