Some statements are given below. Correct statement among the following is
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a
Uncertainity principle is representeed as ΔE .Δt ≥h4π
b
‘m’(magnetic quantum number) value for dx2-y2 orbital is zero
c
Two electrons occupying the same orbital are distinguished by magnetic quantum number
d
According to Schrodinger wave equation, electron behaves like a wave but not like a particle.
answer is A.
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Detailed Solution
ΔE = mΔv2 = mΔxΔt2ΔE.Δt = mΔx2Δt −−−−(1)Δx.mΔv = h4πΔx.mΔxΔt = h4πm.Δx2Δt = h4π−−−(2)Comparing (1) and (2)ΔE.Δt = h4π(2) for pz orbital....m=0; dz2 orbital....m = 0(3) Electrons in an orbital are distinguished by spin quantum number(4) According to SWE, electron is a wave particle