The species in which the central atom uses sp2−hybrid orbitals in its bonding is
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a
PH3
b
NH3
c
CH3+
d
SbH3
answer is C.
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Detailed Solution
In CH3+, carbon atom is in sp2−hybridized state.H=12V+X−Ca PH3=12 5+3=4⇒ sp3b NH3=12 5+3=4⇒ sp3c CH3+=12 4+3−1=3⇒ sp2a SbH3=12 5+3=4⇒ sp3Where, V=number of valence shell electrons of central atom. X = number of monovalent atoms. C = Charge on the species(including sign)