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Q.

The species which has four unpaired electron is :

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a

Co(CN)64−

b

CrH2O63+

c

FeCl42−

d

FeH2O63+

answer is C.

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Detailed Solution

Co(CN)64−→1unpaired electron CrH2O63+→3 unpaired electrons  FeCl42−→4 unpaired electrons.  FeH2O63+→5 unpaired electrons
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