First slide

Conductivity , Molar conductivity and Equivalent Conductivity

Question

Specific conductance of 0.1 M Nitric acid is 6.3 × 10^–2 ohm^–1 cm^–1. The molar conductance of the solution is

Moderate

A

630 ohm^–1 cm²mole^-1
B

315 ohm^–1 cm² mole^-1
C

100 ohm^–1 cm² mole^-1
D

6300 ohm^–1cm² mole^-1

Solution

${\lambda _m} = \kappa \times \frac{{1000}}{M}$

$λ_{m}$ $= \frac{630 \times 10^{- 2} \times 1000}{0.1} = 630 ohm {cm}^{2} {mole}^{- 1}$

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