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Q.

The specific conductivity of a saturated solution of AgCl is 3.40×10−6Ohm−1 cm−1 at 25oC. If λAg+=62.3 ohm−1 cm2 mol−1 and λCl−=67.7 ohm−1 cm2 mol−1, the solubility of AgCl at 25oC is

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a

2.6×10−5 mol L−1

b

3.731×10−3 mol L−1

c

3.731×10−5 mol L−1

d

2.6×10−3 g L−1

answer is A.

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Detailed Solution

λAgCl∞=62.3+67.7=130 ohm−1 cm2 mol−1S=3.4×10−6×103130 mol/cm3=2.6×10−5 mol/L
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