The specific heats of iodine vapor and solid are 0.031 and 0.055 cal/g respectively. If heat of iodine is 24 cal/g at 200°C, then its value of 250°C is
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a
5.7 cal g-1
b
11.4 cal g-1
c
22.8 cal g-1
d
45.6 cal g-1
answer is C.
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Detailed Solution
Solid I2 is converted in I1 vaporI2(s)=I2(g) ΔH=24cal/g at 200∘CΔCp=(CP)2(g)=CpI2(s)=0.031−0.055=−0.24 cal g−1From Kirchhoff's equationΔH250∘C−ΔH200∘C=ΔCpT250∘C−T200∘CΔH250∘C=24−0.024(523−473)=24−1.2=22.8calg−1