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Q.

The specific heats of iodine vapor and solid are 0.031 and 0.055 cal/g respectively. If heat of iodine is 24 cal/g at 200°C, then its value of 250°C is

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a

5.7 cal g-1

b

11.4 cal g-1

c

22.8 cal g-1

d

45.6 cal g-1

answer is C.

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Detailed Solution

Solid I2 is converted in I1 vaporI2(s)=I2(g) ΔH=24cal/g at 200∘CΔCp=(CP)2(g)=CpI2(s)=0.031−0.055=−0.24 cal g−1From Kirchhoff's equationΔH250∘C−ΔH200∘C=ΔCpT250∘C−T200∘CΔH250∘C=24−0.024(523−473)=24−1.2=22.8calg−1
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