The specific rotation of a pure substance is +2.5°. What is the specific rotation of a mixture containing 7 5% of this isomer and 25% of the (-) isomer?
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a
+1.68°
b
0°
c
+0.84°
d
+1.25°
answer is D.
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Detailed Solution
Specific rotation of a mixture containing 75% of (+) and 25% of the (-) isomer= Specific rotation of pure substance ×% of d−% of l100=+2.5×75−25100=+2.5×0.5=+1.25∘