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Q.

The speed of an electron in the inner most orbit of the hydrogen (Bohr radius = 52.9 pm; me = 9.11 × 10–31 kg) is

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a

2.19 × 104 m.s–1

b

2.19 × 106 m.s–1

c

2.19 × 107 m.s–1

d

2.19 × 108 m.s–1

answer is B.

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Detailed Solution

= 2.18 × 108 cm/s= 2.18 x106 m/s.
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