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The spin only angular momentum of unpaired electron in copper atom is
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a
32ħ
b
ħ2
c
34ħ
d
0
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Correct option is A
Spin angular moment =S(S+1)h2π=S(S+1)ħS=12=1212+1ħ=32ħSimilar Questions
At 200°C,hydrogen molecule have velocity 2.4 × 105 cm s-1. The de Broglie wavelength in this case is approximately
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