First slide

Quantum mechanical model of the atom

Question

The spin only angular momentum of unpaired electron in copper atom is

Moderate

A

$\frac{\sqrt{3}}{2} ħ$
B

$\frac{ħ}{2}$
C

$\frac{\sqrt{3}}{4} ħ$
D

0

Solution

$Spin angular moment = \sqrt{S (S + 1)} \frac{h}{2 π} = \sqrt{S (S + 1)} ħ$
$\begin{array}{l} S = \frac{1}{2} \\ = \sqrt{\frac{1}{2} (\frac{1}{2} + 1)} ħ = \frac{\sqrt{3}}{2} ħ \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App