Spin only magnetic moment of $$Cr2+$$ is equal to

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Infinity Learn · Accepted Answer

Spin only magnetic moment, μ$$s=nn+2$$ B.M ; $$n=number$$ of unpaired electrons ;One B.M (Bohr$$ $$Magneton) $$=$$ $$9.273$$×$$10-24$$ A.$$m2$$ ;$$Sc3+$$, $$Ti4+$$, $$Cu+$$, $$Zn2+$$…..$$n=0$$, μ$$s=0$$ ; $$DiamagneticTi3+$$, $$Cu2+$$…..$$n=1$$, μ$$s=3=1.732$$ B.$$M=1.732$$×$$9.273$$×$$10-24$$ A.$$m2$$ ;$$Ti2+$$, $$V3+$$, $$Ni2+$$…..$$n=2$$, μ$$s=8=2.82$$ B.$$M=2.82$$×$$9.273$$×$$10-24$$ A.$$m2$$ ;$$Cr3+$$, $$V2+$$,$$Co2+$$…..$$n=3$$, μ$$s=15=3.87$$ B.$$M=3.87$$×$$9.273$$×$$10-24$$ A.$$m2$$ ;$$Co3+$$, $$Fe2+$$, $$Mn3+$$, $$Cr2+$$…..$$n=4$$, μ$$s=24=4.9$$ B.$$M=4.9$$×$$9.273$$×$$10-24$$ A.$$m2$$ ;$$Fe3+$$, $$Mn2+$$…..$$n=5$$, μ$$s=35=5.9$$ B.$$M=5.9$$×$$9.273$$×$$10-24$$ A.$$m2$$ ;μobs>μcal ......$$Fe2+$$, $$Co2+$$, $$Ni2+$$ ; In these cases orbital contributon cannot be ignored.

Spin only magnetic moment of Cr²⁺ is equal to

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Spin only magnetic moment of Cr2+ is equal to

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Spin only magnetic moment of Cr²⁺ is equal to