Q.
Standard enthalpies of formation of CO2, H2O and C2H4 are -396 kJ/mole - 288 kJ/mole and +52 kJ/ mole respectively. Enthalpy of combustion of Ethene is
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answer is 3.
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Detailed Solution
GivenCs+O2g→ CO2g;ΔH=−396kJ→1H2g+12O2g→ H2Og;ΔH=−288kJ→22Cs+2H2g→ C2H4g;ΔH=+52kJ→3RequiredC2H4g+3O2g→ 2CO2g+2H2Ol;ΔH=?2×Eq1+2Eq2−Eq3ΔH=2−396+2−288−+52=−792−576−52=−1420kJ/mole
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