Q.

Standard Enthalpy of formation of water is -285kJ/mole. Enthalpy of neutralization of strong acid and strong base is -57 kJ/mole. From the heat released by the formation of one mole of liquid water from its constituent elements in their standard states, the number of moles of liquid water that can be ionized will be

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a

3

b

5

c

10

d

6

answer is B.

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Detailed Solution

Given H2g+12O2g→H2Ol ;      ∆H=-285 kJ/mole;.....I; H+aq+OH-aq→H2Ol ; ∆H=-57 kJ/mole;.......II;  Ionisation of one mole of water H2Ol→H+aq+OH-aq ; ∆H=+57 kJ/mole;...III; Heat liberated from Eq I(285 kJ/mole) is utilized in Eq III; Number of moles of water ionized=28557moles=5 moles;
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Standard Enthalpy of formation of water is -285kJ/mole. Enthalpy of neutralization of strong acid and strong base is -57 kJ/mole. From the heat released by the formation of one mole of liquid water from its constituent elements in their standard states, the number of moles of liquid water that can be ionized will be