Q.

The standard equilibrium constant, Kpat 298 K for the reaction, N2(g) + 3H2(g) ⇌ 2NH3(g) is 5.8 x 105. The value of standard equilibrium  constant, if the concentration of gases is expressed  in terms of mol/L, will be:  [Given: R = 0.08314 L bar K-1 mol-1]

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answer is 3.

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Detailed Solution

N2g  +   3H2g   →     2NH3gΔng =  nPg  −  nRg=  2−4=−2KP=KCRT−2KC=KPRT2= 5.8 x  105 (0.08314 x 298)2  =  5.8 x 105 (613.24)  = 3.56 x  108  M–2
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