Q.
The standard equilibrium constant, Kpat 298 K for the reaction, N2(g) + 3H2(g) ⇌ 2NH3(g) is 5.8 x 105. The value of standard equilibrium constant, if the concentration of gases is expressed in terms of mol/L, will be: [Given: R = 0.08314 L bar K-1 mol-1]
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answer is 3.
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Detailed Solution
N2g + 3H2g → 2NH3gΔng = nPg − nRg= 2−4=−2KP=KCRT−2KC=KPRT2= 5.8 x 105 (0.08314 x 298)2 = 5.8 x 105 (613.24) = 3.56 x 108 M–2
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