First slide

Standard EMF of a cell

Question

The standard potentials (E⁰) for the half reactions are as
$\large Zn\, \to \,Z{n^{2 + }} + \,2{e^ - };\,{E^0}\, = \, + 0.76\,V$
$\large Fe\, \to \,F{e^{2 + }} + \,2{e^ - };\,{E^0}\, = \, + 0.41\,V$
the emf for the cell reaction
$\large F{e^{2 + }}\, + \,Zn\, \to \,Z{n^{2 + }} + \,Fe$ is

Easy

Solution

Electrode with higher SOP is anode and with lower SOP is cathode.
$E_{cell}^o = SO{P_{\left( {anode} \right)}} - SO{P_{\left( {cathode} \right)}} = 0.76 - 0.41 = 0.35V$

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