The standard reduction potential for Zn2+/Zn,Ni2+/Ni and Fe2+/Fe are −0.76,−0.23and -0.44 V respectively. The reaction X+Y2+⟶X2++Y will be spontaneous if
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a
X=Ni,Y=F
b
X=Ni,Y=Zn
c
X=Fe,Y=Zn
d
X=Zn,Y=Ni
answer is D.
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Detailed Solution
A cell reaction is spontaneous, if ΔG∘<0Since, ΔG∘=−nFcell ∘Thus, Ecell∘>0 Ecell ∘=Eoxi ∘+ERed∘ (a) X = Ni, Y = Fe Ni+Fe2+⟶Ni2++Fe ENi/Ni2+o=0.23 VE∘Fe2+/Fe=−0.44 V Thus, Ecell ∘=ENi/Ni2+∘+EFe2+/Fe∘ =-0.21 V Ecell ∘<0,reaction is non-spontaneous.(b) X = Ni, Y = Zn, Ni+Zn2+⟶Ni2++Zn ENi/Ni2+=0.23V,EZn2+/Zn∘=−0.76V Ecell ∘=−0.53V Ecell α<0 reaction is non- spontaneous.(c ) X=Fe,Y=Zn,Fe+Zn2+⟶Fe2++Zn Ecell ∘=EFe/Fe2+∘+EZn2+/Zn∘=0.44−0.76=−0.32V Ecell ∘<0, reaction is non- spontaneous.(d) X=Zn,Y=Ni Zn+Ni2+⟶Zn2++Ni Ecell ∘=EZn/Zn2+∘+ENi2+/Ni∘=0.76−0.23=0.53V The reaction is spontaneous.