The standard reduction potentials of Zn2+ | Zn and Cu2+ | Cu are –0.76 V and + 0.34 V respectively. What is the cell e.m.f (in V) of the following cell? Zn | Zn2+ (0.05 M || Cu2+ (0.005 M | Cu.

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1.1295

1.0705

1.1

1.041

answer is B.

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Detailed Solution

Zn+Cu2+0.005M→Zn2+0.05 M+ Cu ;Applying Nernst equationEcell=Eco-Eao-0.05912logZn+2Cu+2Ecell =(0.34+0.76)-0.05912log[0.05][0.005]=1.1-0.03=1.07 V

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