In the standardisation of Na2S2O3 using K2Cr2O7 by iodometry, the equivalent weight of K2Cr2O7 is
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a
molecular weight/2
b
molecular weight/6
c
molecular weight/3
d
same as molecular weight
answer is B.
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Detailed Solution
In this reactionCr2O32− is changed into Cr+3 ion.So, equivalent weight of K2Cr2O7 = molecular wt.decrease of oxidation number × n(where n = No. of atoms of Cr)=molecular wt.3 × 2=molecular wt.6