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Statement 1: ${AlCl}_{3}$ forms dimer ${Al}_{2} {Cl}_{6}$ in gaseous state but it dissolves in $H_{2} O$ forming ${[Al {(H_{2} O)}_{6}]}^{3 +}$ and $3 {Cl}^{-}$ ions.
Statement 2: Aqueous solution of ${AlCl}_{3}$ is acidic due to hydrolysis.

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Both statements 1 and 2 are correct

Statement 1 is correct and statement 2 is incorrect

Statement 1 is incorrect and statement 2 is correct

Both statements 1 and 2 are incorrect

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Correct option is A

Statement 1: In gaseous phase and in non-polar solvent like benzene AlCl3 exists as dimer, Al2Cl6. High enthalpy of hydration in water breaks the covalent dimer forming AlH2O63+ and 3Cl−.Statement 2: AlCl3 + 3H2O → AlOH3 + 3HCl

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Statement 1: AlCl3 forms dimer Al2Cl6 in gaseous state but it dissolves in H2O forming AlH2O63+ and 3Cl− ions.Statement 2: Aqueous solution of AlCl3 is acidic due to hydrolysis.

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Statement 1: ${AlCl}_{3}$ forms dimer ${Al}_{2} {Cl}_{6}$ in gaseous state but it dissolves in $H_{2} O$ forming ${[Al {(H_{2} O)}_{6}]}^{3 +}$ and $3 {Cl}^{-}$ ions.
Statement 2: Aqueous solution of ${AlCl}_{3}$ is acidic due to hydrolysis.