Statement I : Aqueous solution of Na2CO3 shows pH > 7.Statement II : Salt of strong base and weak acid undergoes anionic hydrolysis.

PH of an aqueous solution of salt of strong base and weak acid (Na2CO3) is given byPH=12PKw+PKa+logC⇒PH>7Salt of strong base and weak acid undergoes anionic hydrolysis,Na2CO3(aq)→2Na+(aq)+CO3-2(aq)Na+ is a derivative of strong base and will not undergo hydrolysis.CO3-2Co-x+H2O⇌HCO3-x-y+OH-x+y;Kh1=KWKa2HCO3-x-y+H2O⇌H2CO3+OH-y+x;Kh2=KwKa1Kh1≫Kh2⇒x≫yKh1=KwKa2=(x-y)(x+y)C0-x⇒KwKa2=x×xC0⇒x=C0KwKa2⇒POH=12PKw-PKa2-logC0⇒PH=12PKw+PKa2+logC0