First slide

Electrolysis

Question

Statement I : During electrolysis of aqueous ${CuSO}_{4}$ using Pt electrodes, $p^{H}$ progressively decreases
Statement II : Electrolysis of aqueous ${CuSO}_{4}$ using Pt electrodes, the solution becomes acidic due to the formation of $H_{2} {SO}_{4}$

Easy

A

Statement I and II are correct
B

Statement I correct and Statement II is incorrect
C

Statement - I is incorrect and Statement - II is correct
D

Both statement - I and II are incorrect

Solution

$\large Cathode:Cu_{\left( {aq} \right)}^{ + 2} + 2{e^ - } \to C{u_{\left( s \right)}}$

$\large Anode:2{H_2}O \to 4{H^ + } + 4{e^ - } + {O_2}$
After electrolysis Cell is left with $H_{2} {SO}_{4}$ which is a strong acid, hence pH decreases.

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