Questions
Statement I : Increase in the atomic radius from B to Al is more than that of consecutive elements of the same group
Statement II : Electrons in penultimate shell of aluminium have greater screening effect
Unlock the full solution & master the concept.
Ready to Test Your Skills?
Check Your Performance Today with our Free Mock Tests used by Toppers!detailed solution
Correct option is A
B - 1s2 2s2 2p1Al - 1s2 2s2 2p6 3s23p1From B to Al as the number of inner shell s and p- orbital electrons increases,shielding effect increases .Since s and p-orbital electrons acts as strong screens hence they can protect the valency electrons from the nucleus effectively,so nuclear forces of attractions on valency electrons decreases,therfore size increases largely from B to Al.Similar Questions
The bond dissociation energy of BF bond in BF3 is 646 kJ mol–1 whereas that of CF in CF4 is 315 kJ mol–1. The correct reason for higher BF bond dissociation energy as compared to that of CF bond is :
Get your all doubts cleared from
Sri Chaitanya experts
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
