First slide

First law of thermo dynamics

Question

Statement I: For an isothermal reversible process, $q = - w$ i.e. work done by the system equals the heat absorbed by the system.
Statement II : Enthalpy change (ΔH) is zero for isothermal process.

Moderate

A

Statement I and Statement II are true.
B

Statement I is true and statement II is false.
C

Statement I is false and Statement II is true.
D

Statement I and Statement II are false.

Solution

From First law of Thermodynamics , $\Delta E=q+W$
For isothermal process , $\Delta T=0$ ; $\Delta E=0$
q+W=0 ; q = - W
$\Delta H = n{C_p}\Delta T$
For isothermal process , $\Delta T=0$ , $\therefore \Delta H=0$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App