Statement I : 0.1M NaCN + 0.05M HCl solution on mixing in equal volume forms a buffer solution
Statement II : The solution after mixing contains a weak acid and its conjugate base and thus acts as buffer
On mixing the following reaction occurs.
NaCN + HCl → HCN + NaCl
t=0 | 0.1 x v | 0.05 x V | 0 |
0.1V - 0.05V = 0.05V | 0.1V - 0.05V = 0 | 0.05 v |
After reaction solution is mixture of weak acid and its salt with strong base, thus acts as buffer solution