Statement I :R−COOH→R−CH2OH, can be achieved by LiAlH4 but not by NaBH4Statement II : LiAlH4 is a stronger reductant than NaBH4

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Both statements I and II are correct

Statement I is correct and statement II is incorrect

Statement I is incorrect and statement II is correct

Both statements I and II are incorrect

answer is A.

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Detailed Solution

LiAlH4 is a better hydride (H-) donar as compared to NaBH4. Carboxylic acids and their derivatives cannot be reduced by NaBH4.

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