Statement 1 : If 200 mL of 0.1 N NaOH is added to 200 mL of 0.1 N solution, then the resulting solution is acidic.
Statement 2 : If milliequivalent of acid is greater than milliequivalnts of base, then upon mixing the solution is acidic.
Meq of NaOH = N x V = 0.1 x 200 = 20; Meq of = N x V = 0.1 x 200 = 20.
Resulting solution is neutral.