Statement 1: 1M aqueous solution of glucose contains 180 g of glucose in 1 kg water.Statement 2: Solution containing one mole of solute in 1000 g of solvent is called one molal solution.

Molality (m)= Numberofmolesofsolute  Weightofsolvent(inkg) Number of moles of solute = 1Weight of solvent = 1 kgThen, molality = l, i.e. one molal glucose C6H12O6.Molecular weight = 180Number of moles =180180=1Weight of water = 1 kgHence, molality of the solution in one.