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Q.

Statement 1: Trihydroxyglutaric acid HO2C−CHOH−CHOH−CHOH−CO2H exists in four stereoisomeric forms; two of which are optically active while the other two are meso-forms.Statement 2: It contains two asymmetric and one pseudoasymmetric carbon atom.

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a

Both statements 1 and 2 are correct

b

Statement 1 is correct and statement 2 is incorrect

c

Statement 1 is incorrect and statement 2 is correct

d

Both statements 1 and 2 are incorrect

answer is A.

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Detailed Solution

If a molecule is divisible into two identical halves and chiral carbon atom is odd.Then −n=3Optically active isomer = 2n−1  −  2n−1/2=2 Meso isomer =  2n−1/2=2
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Statement 1: Trihydroxyglutaric acid HO2C−CHOH−CHOH−CHOH−CO2H exists in four stereoisomeric forms; two of which are optically active while the other two are meso-forms.Statement 2: It contains two asymmetric and one pseudoasymmetric carbon atom.