Statement 1: Trihydroxyglutaric acid HO2C−CHOH−CHOH−CHOH−CO2H exists in four stereoisomeric forms; two of which are optically active while the other two are meso-forms.Statement 2: It contains two asymmetric and one pseudoasymmetric carbon atom.
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a
Both statements 1 and 2 are correct
b
Statement 1 is correct and statement 2 is incorrect
c
Statement 1 is incorrect and statement 2 is correct
d
Both statements 1 and 2 are incorrect
answer is A.
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Detailed Solution
If a molecule is divisible into two identical halves and chiral carbon atom is odd.Then −n=3Optically active isomer = 2n−1 − 2n−1/2=2 Meso isomer = 2n−1/2=2
Statement 1: Trihydroxyglutaric acid HO2C−CHOH−CHOH−CHOH−CO2H exists in four stereoisomeric forms; two of which are optically active while the other two are meso-forms.Statement 2: It contains two asymmetric and one pseudoasymmetric carbon atom.