Statement-I: Aniline cannot be prepared by Gabriel phthalimide synthesisStatement-II: Aniline is a primary aryl amine.
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a
Both statements I and II are correct
b
Statement-I is correct and statement-II is incorrect
c
Statement-I is incorrect and statement-II is correct
d
Both statements I and II are incorrect
answer is A.
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Detailed Solution
The main step in Gabriel phthalimide synthesis is ‘X’ on alkaline hydrolysis gives R-NH2In step I instead of R - X if we take C6H5-X we get C6H5NH2. But this is not possible;C6H5-X cannot be attacked by the nucleophile because C6H5-X stabilizes through resonance, C-X acquires double bond character;It is non reactive towards nucleophilic substitution;