The static electronic charge on the oil drop is -6.408×10-19C How many electrons are present on it ?

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Zero

answer is C.

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Detailed Solution

Charge of one electron = -1.602×10-19CAccording to Millikan's oil drop experimentq=ne ⇒n=qe Number of electrons(n) =-6.408×10-19-1.602×10-19=4

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