Structure of a mixed oxide is cubic close packed (ccp). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of oxide is

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AB O2

A2BO2

A2B3O4

AB2O2

answer is D.

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Detailed Solution

From ccp arrangement, number of O2- ions = 4Number of octahedral voids = 4Thus, number of tetrahedral voids = 4 x 2 = 8∴ Number of tetrahedral voids occupied by divalentMetal A=14×8=2.Number of monovalent metal B - Number of octahedral void = 4 ∴Formula is A2B4O4 = AB2O2.

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