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a
CrClO43
b
KMnO4
c
TiCl3
d
VOBr2
answer is B.
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Detailed Solution
As we know, magnetic momentμ=n(n+2) BMKMnO4 +7 n = 0 diamagneticCr(ClO4)3 +3 n =3 paramagneticTiCl3 +3 n = 1 paramagneticVOBr2 +4 n = 1 paramagnetic