The sulphate of a metal M contains 9.87% of M. This sulphate is isomorphous with ZnSO4⋅7H2O. The atomic weight of M is
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a
40.3
b
36.3
c
24.3
d
11.3
answer is C.
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Detailed Solution
As the given sulphate is isomorphous with ZnSO4⋅7H2O its formula would beMSO4⋅7H2O⋅m is the atomic weight of M, Molecular weight of MSO4⋅7H2O=m+32+64+126=m+222Hence % of M =mm+222×100=9.87 (given) or100m=9.87m+222×9.87 or 90.13m=222×9.87 or m=222×9.8790.13=24.3