The sulphate of a metal ‘M' contains 9.87% of ‘M’. This sulphate is isomorphous with ZnSO4.7H2O. The atomic weight of ‘M' is

As the given sulphate is isomorphous with ZnSO4.7H2O , its formula would be MSO4.7H2O.  Let ‘m’ be the atomic weight of ‘M’, molecular weight of MSO4.7H2O                        =m+32+64+126=m+222Hence  %  of M=mm+222 × 100=9.87givenor100m=9.87m+222×9.87  or  90.13m=222  ×  9.87or     m=222 ×  9.8790.13=24.3