Sulphurous acid H2SO3 has ka1=1.7×10−2 and ka2=6.4×10−8 . The pH of 0.588M H2SO3 is ______ (round off the Nearest Integer)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

ka1>>ka2H2SO3⇌H++HSO3− C(1−α) Cα CαKa1=Cα21−α H+=Cα=0.092∴PH=−log⁡(0.092) =1.036≅1

Watch 3-min video & get full concept clarity