First slide

Terms used in complex chemistry

Question

The sum of coordination number and oxidation number of the metal M in the complex $[M (e n)_{2} (C_{2} O_{4})] Cl$ (where en is ethylenediamine) is

Easy

A

6
B

7
C

8
D

9

Solution

$[M (en)_{2} (C_{2} O_{4})] Cl :$
en…neutral, bidentate
oxolato…bivalent,negative,bidentate
Oxidation number of metal = +3
Coordination number of metal = 6
$∴$ Sum of oxidation number and coordination number = 3 + 6 = 9

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