The sum of the number of lone pairs of electrons on each central atom in the following species is TeBr62−,BrF2+,SNF3, and XeF3- (Atomic numbers: N=7,F=9,S=16,Br=35,Te=52, Xe=54)
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 6.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Species Number of lone pairs+4−6TeBr6−2 → 1⇒Te=5s2,5p4(16 th group ),Te+4=5s25p0(1lp)+3−2BrF2+ → 2⇒Br=4s2,4p5 (17th group), Br+3=4s24p2(2lp)SNF+63−3 → 0⇒S=3s2,3p4(16 th group ),S+6=3s03p0( Zero lp)+2−3XeF3−1 → 3⇒Xe=5s2,5p6(18th group ),Xe+2=5s25p4(3lp)∴ Sum is =1+2+0+3=6 lone pairs
The sum of the number of lone pairs of electrons on each central atom in the following species is TeBr62−,BrF2+,SNF3, and XeF3- (Atomic numbers: N=7,F=9,S=16,Br=35,Te=52, Xe=54)