Q.

The sum of the number of lone pairs of electrons on each central atom in the following species is TeBr62−,BrF2+,SNF3, and XeF3- (Atomic numbers: N=7,F=9,S=16,Br=35,Te=52, Xe=54)

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answer is 6.

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Detailed Solution

Species                 Number of lone pairs+4−6TeBr6−2   →        1⇒Te=5s2,5p4(16 th group ),Te+4=5s25p0(1lp)+3−2BrF2+  →          2⇒Br=4s2,4p5 (17th group), Br+3=4s24p2(2lp)SNF+63−3       →           0⇒S=3s2,3p4(16 th group ),S+6=3s03p0( Zero lp)+2−3XeF3−1     →        3⇒Xe=5s2,5p6(18th group ),Xe+2=5s25p4(3lp)∴ Sum is =1+2+0+3=6 lone pairs
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