Covalent Bonding

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Question

The sum of the number of lone pairs of electrons on each central atom in the following species is:
${[{TeBr}_{6}]}^{2 -}, {[{BrF}_{2}]}^{+}, {SNF}_{3} and {XeF}_{2}$
$[At. Nos. N = 7, F = 9, S = 16, Br = 35, Te = 52, Xe = 54]$

Moderate

Solution

$\begin{array}{l} {[{TeBr}_{6}]}^{2 -} - One lone pair. \\ {[{BrF}_{2}]}^{+} - Two lone pairs. \\ {SNF}_{3} - Nil lone pair. \\ {XeF}_{2} - Three lone pairs. \end{array}$

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