On supplying 250J  heat to a gas, its 2L volume at .N T.P. becomes 2.2 Lat one atmoephere. The change  in ifs internal energy would be:

Work done at constant P is negative and irreversible. ∴ W=−PV2−V1=−1abn(2.2−2)L=−0.2Latin=−0.2×1.987×4.1840.0821J=−20.25J∵1L atom =1.987×4.1840.0821JBut ∆U=q+W;ΔU=250J−20.25     =229.75JSo, the correct answer is (3)