Q.

Suppose 5 g of CH3COOH is dissolved in one litre of Ethanol. Assume no reaction between them. Calculate molality of resulting solution if density of ethanol is 0.789 g/ml.

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0.0856

0.0956

0.1056

0.1156

answer is C.

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Detailed Solution

Weight of CH3COOH dissolved = 5 gMoles of CH3COOH dissolved =560Volume of ethanol = 1 litre = 1000 ml.∴ Weight of ethanol =1000×0.789=789g∴ Molality of solution m=Moles of solutewt. of solvent in kg=560×7891000=0.1056

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